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I just want to remind you of the main facts. The first thing that you have to do is, of course, we are going to have to be doing it several times today. That is the system we are trying to solve. And the first thing you have to do is find a characteristic equation which is general form, although this is not the form you should use for two-by-two, is A minus lambda I equals zero. And its roots are the eigenvalues. And then with each eigenvalue you then have to calculate its eigenvector, which you do by solving the system (A minus lambda1, let's say, times I) alpha equals zero because the solution is the eigenvector alpha 1. And then the final solution that you make out of the two of them looks like alpha 1 times e to the lambda 1t. Of course you do that for each eigenvalue. You get the associated eigenvector. And then the general solution is made up out of a linear combination of these individual guys with constant coefficients. The lecture today is devoted to the two ...

So just trying to remind you that the replication fork looks something like this where 5 prime to 3 prime and 5 prime to 3 prime. This is what's known as the leading strand because DNA, the synthesis of the new strand can go -- Which is going 5 prime to 3 prime is going in the same direction as the movement of the replication fork. The other strand, which is known as the lagging strand, the DNA synthesis is actually going backwards to the movement of the replication fork, which means it has to go and then start up here and go again. And it's continually jumping. And I told you that the little RNA primer is used to start each strand. And then the DNA polymerase is able to elongate that. And then at the end these little nicks in here, the RNA has to be removed, fill in the gap and then it's sealed up by the enzyme DNA ligase, which we'll talk about when we talk about recombinant DNA. Someone asked, I had mentioned why this strategy of using RNA was beneficia...

JUDY HOYT: Just remind people where we are on the course schedule, we just finished up chapter 9 on deposition and epitaxy, and we're going to plow ahead, moving along to chapter 10, which we'll cover in the next couple of lectures. Chapter 10 is on etching, which is a very important capability for CMOS processing. And today is the 18th, and I guess homework number 5 is due today. So I brought a new folder here up front, this yellow folder, we'll use to hold your homework number 5. I'm going to have-- homework number 4's been graded, but I need to go through it. So I'll have that back to you next week. So let's take a look at today's handout, which is handout number 33, and we're starting chapter 10 on etching. We've talked a lot about, now, a lot of different processes. We spent the last three lectures talking about depositing thin films. After they're deposited, typically they have to be etched to make some kind of a circuit p...